Example
involving Friction
For the first case, assume the block tends to
slide up the plane and construct a FBD. Note
the directions taken for + x and + y.
Then write the equations of equilibrium. ΣFy = 0 N - P sinθ
˗ Q cosθ
= 0
(1) ΣFx
= 0 ˗ F + P
cosθ ˗ Q sinθ = 0 (2) So from eq.
1 N
= P sinθ + Q cosθ The maximum value for friction is Fmax = μs
N
So from eq. 1 F
= μs
[P sinθ
+ Q cosθ ] (3) Next put eq. 3 and eq. 2 and solve for P . P
= Q ( sinθ
+ μs cosθ
) / (cosθ ˗ μs
sinθ ) For the prescribed values for Q, θ, and μs gives
P = 483 N. (result) Next consider the possibility that the block
slides down the plane.
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