Example involving Friction

 

For the first case, assume the block tends to slide up the plane and construct a

FBD.  Note the directions taken for + x and + y.  Then write the equations of

equilibrium.

                                  

 

 

         ΣFy  =  0            N - P sinθ ˗ Q cosθ  =  0                                                    (1)

 

         ΣFx  =  0          ˗  F +  P cosθ  ˗  Q sinθ  =  0                                               (2)

 

So  from eq. 1           N  =   P sinθ  +  Q cosθ 

 

The maximum value for friction is      Fmax = μs N                                             

 

So from eq. 1                   F =  μs [P sinθ  +  Q cosθ  ]                                         (3)

 

Next put eq. 3 and eq. 2  and solve for  P .

 

                      P  =  Q ( sinθ + μs cosθ ) / (cosθ ˗ μs sinθ ) 

 

For the prescribed values for  Q, θ, and μs  gives      P = 483 N.      (result)

 

Next consider the possibility that the block slides down the plane.                    

 

Click here to continue with this problem.

 



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