Structures under
Combined Loading
t = (Mx)r/
J =
(2000)(0.95)/(0.6) = 3167 psi The
figures below show the element at B with faces C and D acted on by normal and shearing
components of stress. Plot these
stresses to form Mohr’s Circle, also shown below. The
center is at (- 2663 + 0)/2 = (- 1332, 0 ) . The
radius is √ (- 1332)2
+ (3167)2 = 3435 psi So
the minimum normal stress is - 1332 -
3435 =
- 4767 psi (result) In
this case the “minimum” normal stress is compressive. |
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