Structures under Combined Loading


Example:  (continued)

For element B :     σ  =  - (My)c/I  + R/A  =  - (900)(0.95)/(0.3) + 150/0.8  =  - 2663 psi

                             t = (Mx)r/ J  =  (2000)(0.95)/(0.6)  =  3167 psi

 

The figures below show the element at B with faces C and D acted on by normal and

shearing components of stress.  Plot these stresses to form Mohr’s Circle, also shown

below.

 

The center is at  (- 2663 + 0)/2 =  (- 1332, 0 ) . 

 

The radius is  √ (- 1332)2 + (3167)2   =  3435 psi

 

So the minimum normal stress is  - 1332 - 3435  =  - 4767  psi      (result)

 

 

            

 

In this case the “minimum” normal stress is compressive.

 


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