Mohr’s
Circle - Stress
Example: (continued) The figure below shows the element with faces A
and B as well as points A
and B on Mohr’s
Circle. The principal stresses (max
and min) are σ1 and σ2 respectively. The radius of the circle is √ [ (1250/π)2 +
(2500/π)2 ]
= 889.7 psi Now σC = 1250/π psi so σ1 =
σC + 889.7 = 1287.6
psi and σ2 =
σC − 889.7
= − 491.8 psi Next the tan(2θ) = (2500/π) / (1250/π) = 2 so 2θ
= 63.43o . For the element θ = 31.71o . For the principal stresses
on the element rotate face A 31.71o clockwise as shown below. Result |
Return to Notes on Solid Mechanics |
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