Center of Gravity, Centroid (example continued)

 

                                                   

 

The element of area, dA, = dx dy  or  dy dx.  Select integration in the y-direction first since it is

the easiest to evaluate.

 

The limits of integration in the y-direction are from   ½ x  to  2x – x2/6 .  Calculate the total

area, A.

 

                                              x = 9      y =  2x – x2/6         x = 9

     dA = dy dx             so  A =                 dy dx          =        ( 2x – x2/6 – ½ x ) dx

                                              x = 0      y = ½ x                  x = 0

 

The result is   A  =  81/4  in2 .

 

Next calculate       y dA  =      y  dy dx

 

 

                           x = 9      y =  2x – x2/6         x = 9

            ycg A =                  y  dy dx          =       [ ( 2x – x2/6 )2 – ( ½ x )2 ]/2  dx

                           x = 0      y = ½ x                  x = 0

 

                          x = 9                                                                                            9

            ycg A =         [ 15/8 x2  +  x4/72  -  x3/3 ]  dx  =   5/8 x3 + x5/360 - x4/12  |

                          x = 0                                                                                            0

 

            ycg A =   [ (9)3 / 2 ][ 5/4 + 81/180 – 3/2 ]  =  81(36)/40  in3

 

So     ycg = [ 81 (36)/40 ] / (81/4)  =  36/10  =  3.60 in.      (result)

 

 

  Return to Notes on Statics

 

Copyright © 2019 Richard C. Coddington
All rights reserved.