Finite Volume Analysis: Application of Conservation of Mass (continued)
Example 1 (continued) Recall strategy for solution:
u/U
= ( y/δ)1/7 d/dt ∫ ρ dV +
∫ ρ v ●n
dA =
0 for steady flow (flow is
established) d/dt ∫ ρ dV = 0 cv cs
cv y = δ ∫ ρ v ●n dA = ρ U i ● n1 A1 +
ρ ∫ U(y/δ)1/7 i ● n2 L dy = 0 cs y = 0 ρ U i
● n1 A1 = -
ρ U A1 =
- ρ Q note:
n1 = - i n2 = i y = δ
y = δ ρ ∫ U(y/δ)1/7
i ● n2 L dy = ρ
U L (7/8) (1/δ)1/7 (y)8/7 |
= (7/8) ρ U Lδ
y = 0
y = 0 So
- ρ Q + (7/8) ρ U Lδ = 0 and
Q = (7/8) U Lδ (result) Click
here for another example. |
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