Fluid Statics Example
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Example 2 of an inclined Barometer with three
different liquids The
inclined barometer shown in the figure below contains cross-hatched liquid 1
with specific
weight, γ1,
on the left, clear liquid 2 with specific weight, γ2,
in the middle, and cross-hatched
liquid 3 with specific weight, γ3,
on the right. The pressure at point A
is PA
in the left vessel and the pressure at point B in the vessel on the right is
PB. Find the pressure
difference between point A and point B in the inclined manometer. Recall
that pressure increases with depth in a liquid column in proportion to the
specific weight
of the liquid. So start at point A and
move to the right. The pressure
changes are: (increases in pressure are + and decreases
in pressure are - ) PA + γ1
h -
γ2
(L sin θ) - γ3
d =
PB Therefore
the pressure differential is: PA - PB = γ2
(L sin θ) + γ3
d - γ1
h (result) |
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