The Parallel Axis Theorem (example continued)
(Strategy continued)
Calculate the centroid of the composite section, ycg :
Σ Ai ycg = ΣAiyi (3bh) ycg = (bh)(h/2) + (bh)(h/2) + (bh)(h + b/2)
ycg = c = [h + h + (h+b/2)] / 3 = (5h + b)/6
Locate the distances of the centroid of the three rectangular areas from the centroid of
the composite section. i.e. d and e
Calculate the moment of inertia of each rectangular area about its own centroidal axis.
Moment of inertias: Izz1 = Izz2 = (1/12)bh3 Izz3 = (1/12) hb3
Use the parallel axis theorem to obtain the moment of inertia of the composite section
about its centroidal axis.
Izzcg1 = Izz1 + (bh)d2 = Izzcg2 and Izzcg3 = Izz3 + (bh)e2
Sum these terms to obtain the total moment of inertia, Izzcg, for the composite area about
its centroid.
Izzcg = Izzcg1 + Izzcg2 + Izzcg3
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