Shear and Bending Moment Diagrams (example continued)

Here’s the FBD for the first portion (section 1) along the beam.

For 0 < x < L/2 Σ Fy = 0 gives V = P/2 and

Σ M_Q = 0 gives M(x) = Px/2

Here’s the FBD for the second portion (section 2) along the beam.

For L/2 < x < L Σ Fy = 0 gives V = - P/2 and

Σ M_Q = 0 gives M(x) = - Px/2 + P (x – L/2) + M = 0 or M(x) = P(L – x)/2

Next plot these results for the shear force and bending moment diagrams.

Click here to continue.

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