Shear
Flow in Beams
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*Example: The nail spacing is 100 mm along a beam with the x-section as shown
below. The force allowed per nail
is 1200 N. Find the maximum allowable
shear force, Vmax. The figure below details
the nail spacing. |
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Strategy: Identify the area, A’, from
where the shear stress is zero to the location where the shear stress is to be
calculated. Evaluate Q recalling that Q = A’ybar.
Apply the relations for shear flow and nail
spacing q = VQ/I
and q =
F/s Consequently F/s
= VQ/I so
V =
FI/Qs where F =
1200 N, I
= (1/12)(260)(310)3
– (1/12)(160)(260)3 = 411 x 106 mm4 s
= 100 mm The challenging
calculation is for Q. Click here to continue
with this example. |
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