Dimensional Analysis   (Using the method of repeating variables)

 

Example:   Water sloshes back and forth in a rectangular tank as shown in the figure below.

Let  ω denote the frequency of sloshing in cycles per second.  Assume that sloshing is a function

of the acceleration of gravity, g, in ft/sec2, the average depth of water in the tank, h, in feet,

and the characteristic length of the tank, L, in feet.  Determine the set of dimensionless

products characterizing sloshing.                          

                                                      

 

Strategy:

1.

Identify variables governing the problem.  (Very important and critical first step)

2.

List dimensions for each variable.  Use dimensions:  F,L, and T 

3.

Number of dimensionless products (Pi terms) =  N   

       number of variables  -  number of dimensions

4.

Select the repeating variables, the dependent variable, and the non-repeating variable.

 

5.

Use the repeating variables to form dimensionless products of the dependent

Variable and the non-repeating variables.

Solution:

Variables

ω (dependent)

h   non-repeating

g  repeating

L   repeating

dimensions

      1/T

        L

      L/T2

      L

 

Number, N, of dimensionless products  =  4 variables - 2 dimensions  =  2

Select repeating variables as follows:

 

Use  g  to eliminate the dimension of time, T, and L to eliminate the dimension of length.

 

Pi terms are:  Pi1  =  h/L   and    Pi2  =  ω2 L/g

 

 

The result is:     ω2 L/g  =  f(h/L)

 

Click here to return to the example using the method of exponents.

Click here for a discussion of similitude.

 


Return to Notes on Fluid Mechanics


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