Torsion of a Circular Bar - Shear Strain

Example: (continued)

Apply: γ L = ρ φ

So γ = ρ φ / L

Now φ = T L / J G

So γ = ρ T / J G

For shear strain at the inner diameter, ρ = d_i / 2

So γ = d_i T / 2 J G

For the data: γ = (10) in (20,000 ft lb) (12 in/ft) / (2)(10540) in⁴ (10⁷ ) lb/in²

= 0.0000114 radians (result)

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