Calculus 1  Hour Exam 1 (continued) -   Math 220     Fall, 2011

 

 

 

 

6.

 

 

Solve for  x  in the equation below.

 

                 ln (x – 4)  +  ln (x – 1)  =  2 ln (5 – x)

 

Answer:    x = 21/5

 

 

 

 

 

 

 

 

 

 

 

 

 

7.

 

Evaluate the following limits.  Show sufficient justification for each answer.

An answer of  ‘does not exist’ is not sufficient.  For infinite limits you must state

If it is  ∞  or   - ∞.

 

a.       lim   [ ( 3x + 1 )2 ] / [ 2x2 + 5 ]

           x→∞

 

 

b.      lim  ( 5 x2 + 2x + 3 ) / ( 7 x2 + 4 )

          x→0

 

 

c.       lim [ √ (9x)  - 3 ] / ( x – 1)

x→1

 

 

d.      lim    [ 1 – (cos x + sin x )2  / (10 x cos x) }

          x→0

 

 

e.       lim  ln ( x/8 )  /  ln ( x/4 )

           x→4-

 

 

Answers:    a.  9/2           b.  ¾           c.  3/2          d.  – 1/5           e.  ∞