Calculus
3 Hour Exam 2 - Math
241 Fall, 2010
1a. |
State, with hypotheses, the second derivative test. |
1b. |
For f(x,y) = ey ( y2 – x2 ), find fx, fy, fxx, fxy, fyy and all critical points. Answers: find fx, = ey(-2x), fy = 2yey + y2 ey, fxx = -2ey, fxy = -2xey fyy = (2 + 4y + y2 )ey Critical points: (0,0) and (0, -2). |
1c. |
Classify the critical points as max, min, saddle, or indeterminate. Answer: (0,0) saddle (0 -2) max |
2a. |
Draw the level curves for f(x,y) = 16x2 – y2 for k = -1, k = 0, k = 1 labeling each branch and intercept. |
2b. |
Use Lagrange multipliers to find the maximal value of f(x,y) subject to the constraint y - x2 = -2. Show work. Answer: Max = 96. |
3a. |
For the region 22 ≤ x2 + y2 + z2 ≤ 42, 2 ≤ y ≤ 3, sketch a slice for some y between 2 and 3. |
3b. |
Set up an integral to find the volume of the region. Answer: y = 3 θ = 2π r = √(16 – y2 ) ∫ ∫ ∫ r dr dθ dy y = 2 θ = 0 r = 0 |
3c. |
Compute the volume. Answer: V = 29π/3 Click here to continue with this exam. |