Implicit Differentiation
In a Nut Shell: Implicit differentiation is
the process of differentiating both sides of an equation and then solving
for the derivative of the dependent variable such as dy/dx. |
Example 1 of implicit differentiation: Find dy/dx given xy =
sin (x) ,
where y =
y(x) Step 1 Take the derivatives of both sides of the
equation. y
+ x dy/dx = cos (x) Step 2 Solve for
dy/dx x dy/dx = cos (x) - y x dy/dx = cos (x) -
sin (x) / x Result: dy/dx = [ cos (x) - sin (x) / x ] / x |
Example 2 Find dy/dx given e 4y - ln (y) = 2x Step 1 Differentiate both sides of
this equation with respect to x. 4 e 4y dy/dx - (1/y) dy/dx = 2 Step 2 Solve for dy/dx [ 4 e 4y -
(1/y) ] dy/dx = 2 Result: dy/dx = 2 y /
[ 4 y e 4y - 1 ]
|
Try this one: Find
dy/dx given cos (y) - y 2 =
8 Step 1 is to differentiate both sides of this
equation. Step 2 is to collect terms and solve for dy/dx Result: dy/dx = 0 provided sin y
- 2y ≠
0 |
Return to Notes for Calculus 1 |
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