Indeterminate
Forms - (continuing discussion)
Type 3: (product) The limit of the function involves 0
. ∞ or
∞ . 0 Procedure: Convert to a quotient
function 0/0 or ∞/∞ using
division; You have then converted the
indeterminate for to a Type 1 where L’Hospital’s
Rule applies. |
Example: lim
[x ln x]
= lim [( ln x ) / 1/x
] =
lim [ (1/x ) / ( ˗ 1/x2) ] x → 0 x → 0 x → 0 lim [ ˗ x ]
= 0 x →
0 |
Type 4: (power) The limit of the function involves 00 , ∞0 , and
1 ∞ Procedure: To evaluate the limit in type 4 first take the logarithm of the function. Then you attempt to put the indeterminate
form into a quotient function (Type 1) and apply L’Hospital’s Rule. Steps: Let y
= [ f(x) ] g(x) , take ln
y =
g(x) ln [ f(x)] then evaluate lim ln y =
L, then lim [ f(x) ] g(x) =
e L x →
a x → a |
Example: Find the limit of y
= [cos
x ] 1/x as x → 0 ln
y =
[ (1/x) ln (cos x)
] lim ln y = lim [ (1/x) ln (cos x) ] = lim [ ln (cos x) ] / x x → 0 x → 0 x → 0 has the Type 1 form 0 / 0 so apply
L’Hospital’s rule directly. lim [ {- sin x / cos
x} / 1 ] = lim ln y = 0 x → 0 x
→ 0 So
y = lim [cos x ] 1/x =
e 0 = 1 x → 0 |
Click here for a summary
of strategies to evaluate indeterminate forms. |
Return to Notes for Calculus 1 |
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