Indeterminate Forms  - (continuing discussion)

 

Type 3:  (product)   The limit of the function involves       0  .      or     . 0

 

Procedure:  Convert to a quotient function  0/0 or  ∞/∞  using  division;  You have

then converted the indeterminate for to a Type 1 where L’Hospital’s Rule applies.

 

 

Example:   lim [x ln x]   =     lim  [( ln x ) / 1/x ]    =  lim [ (1/x ) / ( ˗ 1/x2) ]

                  x → 0                  x → 0                          x → 0   

 

                                lim [ ˗ x ]  =  0

                                x → 0   

 

 

Type 4:  (power)   The limit of the function involves         00 ,  0 ,  and   1    

 

Procedure:  To evaluate the limit in   type 4    first take the logarithm of  the

function.  Then you attempt to put the indeterminate form into a quotient function

 (Type 1) and apply L’Hospital’s Rule.

 

 

Steps:           Let   y  =  [ f(x) ] g(x)    ,      take ln y  =  g(x) ln [ f(x)]   then

 

                     evaluate   lim  ln y    =  L,   then  lim [ f(x) ] g(x)  =   e L

                                      x → a                          x → a

                              

 

Example:      Find the limit of      y  =  [cos x ] 1/x    as  x → 0

 

                  ln y  =  [ (1/x) ln (cos x) ]

 

                    lim  ln y   =  lim  [ (1/x) ln (cos x) ]    =  lim  [ ln (cos x) ] / x

                    x → 0         x → 0                                  x → 0

 

        has the Type 1 form     0 / 0    so apply  L’Hospital’s rule directly.

                           

 

                lim  [ {- sin x / cos x} / 1 ]  =   lim  ln y   =  0

              x → 0                                        x → 0

 

        So    y   =    lim  [cos x ] 1/x    =   e 0   =  1

                         x → 0

 

 

Click here for a summary of strategies to evaluate indeterminate forms.

 



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