Example: Find the
number of terms needed to find the sum of the series
∞
∑ 10/n8 to three decimals.
n = 1
Note that the series is
a positive term p-series with p =
8. Therefore the series converges
and has a sum. Also the series satisfies the conditions
for the integral test. Note the
improper integral
expression for Rn
.
∞
t
Rn ≤
ʃ (10/x8) dx =
lim (10 x˗7 / ˗7)
| =
(10/7) n˗7
< 0.0005
x = n
t→∞ n
Note: To
estimate the sum to within three decimal places, one must make certain
the remainder is less
than 0.0005.
Solve for n. n7 > 2857.15 n > 3.1
So n = 4
R4 =
10/18 + 10/(28) +
10/(38) + 10/(48) ~
10.041 (result)
after rounding to three
decimal places
|