∞ ∞
For
what values of x does a Power Series Converge? ∑ an (x b)n =
∑ un
n=0 n=0
|
|
Heres a reminder of the Ratio Test for the Power Series given at the
top. To test, take the
limit: lim | (un+1)/ un | =
lim | (an+1)(x- b)n+1/
an (x b)n| n → ∞ n → ∞ which becomes lim
| {(an+1)/an }(x b)| =
P |x -b| n → ∞ For convergence P |x - b|
< 1 so
|x - b| < 1/P =
R (radius of convergence) |
|
Step 1 Find radius of
convergence
∞
Consider
the example ∑ (x 1)n Here un
= (x 1)n un + 1 =
(x 1)n + 1 n=0 lim
| (un+1)/ un |
= lim | x 1 |
< 1 R
= 1 for convergence n → ∞ n → ∞ or - 1
< (x 1) <
1 |
|
Step 2 Plot the interval of
convergence on the real axis.
converges here __________________|_________|_________|______________ x
0 1 2 |
|
Step 3 Check end points of
interval. In this example the two end
points are x =
2 nd x
= 0. Put them in the original power series to
obtain a series of constant terms. You then use any of the
tests for an infinite series of constant terms to determine convergence or divergence. ∞ For x
= 0, ∑ ( 1)n diverges by nth term test or since
series alternates n=0 ∞ For x
= 2, ∑ ( 1 )n diverges by nth term test n=0 Result: Interval of convergence = (
0 , 2) Radius of convergence = 1. Click here for other
examples. |
Copyright © 2017 Richard C. Coddington
All rights reserved.