Example 6: ∫
sec x dx
Multiply and divide sec x by (sec x + tanx)
and let
u = sec x + tanx, du = (sec x tan x + sec2x ) dx
So integral becomes ∫ du / u = ln |u| + C
∫ sec x dx =
ln | sec x + tan x | +
C
Use similar strategy for ∫ csc x dx (don’t
forget – sign)
∫ csc
x dx
= - ln
| csc x + cot x | +
C
|