Newton's Method

 

 

Example:  Find the value of  (75)1/4  to five decimal places.

 

 

Recall Strategy:

 

 

  1.

 

Write down the expression for f(x).   In this example,  f(x)  =  x4  ˗  75  = 0 

and  f '(x)  =  4 x3  .

 

 

  2.

 

Set up a table with columns for   xn  ,  f(xn) ,  f ' (xn) ,   f(xn) / f ' (xn) , and  xn+1  . 

See below.

 

 

  3.

 

Identify the starting value,  x1.   In this example  24  =  16  and   34 =  81

So pick the value of  3 for the starting value of  x.

 

 

 

  4.

 

Once the value for the root,  xn+1  is found, it represents the new

value for xn .  Repeat the iteration until reaching the desired accuracy.

 

 

 

 

   n         xn                    (xn)4  ˗  75              4 (xn)3                 [(xn)4  ˗ 75] / 4 (xn)3             xn+1 

1

    3.0

        6.0

   108.0

0.055555555

2.94444444

2

2.94444444

0.16461857

102.110425

0.001612162

2.94283228

3

2.94283228

0.00013515

101.942792

0.000001326

2.94283095

 

 

 

Result:   The value of    (75)1/4    is approximately   2.94283  .

 

 

 

Click here for another example.

 


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