Rewrite: f(x) =
4 / ( 5 + x )3
= (4/53) 1 / (1 +
x/5)3 = (4/53) (1 + x/5) ˗3
By the binomial theorem:
(1
+ x/5) ˗3 = 1 ˗
3[ (x/5) + (˗4)(x/5)2 /2!+ (˗4)(˗5)(x/5)3
/3! + .
. . ]
∞
So f(x)
= (4/53) ∑ ( { ˗ 3 / n
} (x/5)n ( result for series of f(x) )
n=0
where { ˗ 3 / n } = [
(˗ 3 ) (˗ 4 ) (˗ 5 ) . .
. ( ˗ 3
˗ n + 1 ) ] / n!
Next find the radius of
convergence of the power series, f(x).
Strategy:
Apply lim | f(x) n+1 / f(x) n
|
n → ∞
= lim | ([(1)(2)(˗3) . . (˗3˗n+2) ] (x/5)n+1/ 2( n+1)!]
/ [ [1)(2)(3) . . (˗3˗n+1) (x/5)n
/ 2 n! ] |
n → ∞
= lim | ([ (˗3 ˗ n + 2 ) (x/5) / ( n+1 )] | <
1 for convergence
n → ∞
= lim | (x/5) | <
1 for convergence or
lim | x | < 5
So R = 5 (result)
n → ∞
n → ∞
|