Green’s Theorem

 

 

Example:  Apply Green’s Theorem to evaluate the work done by the force vector, F, going

completely around the square region, R, (shown below) counterclockwise.

 

  Work  =     F . dr     =       [∂Q/∂x  -  ∂P/∂y] dA 

                   C                     R

 

       where             F  =  [ y / (x2 + y2) ] i   - [  x / (x2 + y2) ] j  =  P i  +  Q j

 

 

 

      

 

                         

                    

 

 

 

Method 1:  Apply         [∂Q/∂x  -  ∂P/∂y] dA 

                   C              R

 

Now    ∂Q/∂x  =  (x2 - y2) / (x2 + y2)2  =   ∂P/∂y 

 

Note that these partial derivatives exist throughout the region, R.  Thus the double integral

over R equals zero since    ∂Q/∂x  =  ∂P/∂y  .

 

 

 

 

Method 2:  Calculate the work done by evaluating the line integral directly around the

curve, C, encompassing the region R.  

 

  Work  =     F . dr     =       [∂Q/∂x  -  ∂P/∂y] dA 

                   C                     R

 

 

Click here to continue with Method 2.

      



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