Autonomous Differential Equations i.e. D.E. of the form dy/dt = f(y)
Example: Find the critical points then sketch the
phase diagram for the following differential equation: dy/dt =
(1/2) y ( y ˗ 2 )2 ( y ˗ 4 ) |
Strategy: Step 1: Find the critical points by setting f(y)
= 0. Critical Points: f(y) =
0 at y = 0,
y = 2,
and y = 4 Step 2: Identify each region where
slopes may change from positive to negative, stay the same, or change from negative
to positive. Evaluate the slopes on
each side of the critical points by taking values
within each region. The four regions in this
example include: y < 0, 0 < y < 2, 2
< y < 4, y
> 4 i.e. For
y = ˗ 1, dy/dt =
45/2 > 0, for y = 1, dy/dt = ˗ 3/2
< 0 For
y = 3, dy/dt = ˗ 3/2
< 0, and for
y = 5, dy/dt = 45/2
> 0 |
Step 3: Plot Phase Diagram: Note: A right directed arrow
indicates that the dependent variable, y, is increasing. A
left directed arrow indicates that the dependent variable, y, is decreasing. Results: At the critical point y = 0,
the response is stable. At
the critical point y = 2, the response is semi-stable. At the critical point y = 4,
the response is unstable. i.e. In the neighborhood of y = 0,
the value of y(t) tends toward a stable value. In the neighborhood of y = 2,
the value of y(t) hovers around a stable value. In the neighborhood of y = 4,
the value of y(t) departs from a stable value. |
Click here to continue
with construction of the slope field for this example. |
Copyright © 2017 Richard C. Coddington
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