Volume
of a Sphere using Rectangular, Cylindrical, and Spherical Coordinates
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The first integration
gives x = R
y = √(R2 – x2) V = 8 ∫ ∫ √(R2 – x2 – y2) dy dx x = 0
y = 0 Notice that the integral
on the variable y has the form ( a2
– y2) where a2 =
R2 – x2. So you could proceed by
using a substitution y = a sin α . But at this point you might instead switch to “polar
coordinates” for the double integral.
Then the integral becomes θ = π/2 r = R V =
∫ ∫ √(R2 – r2) r dr dθ θ = 0 r =
0 Let w = R2 – r2 so dw = - 2r dr and r dr = - ˝ dw Click here to continue
with this example. |
Copyright © 2017 Richard C. Coddington
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