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Structures under Combined Loading

Example: (continued)

For element A : σ = (M_z)c/I + R/A = (1500)(0.95)/(0.3) + 150/0.8 = 4938 psi

t = (M_x)r/ J = (2000)(0.95)/(0.6) = 3167 psi

The figures below show the element at A with faces C and D acted on by normal and

shearing components of stress. Plot these stresses to form Mohr’s Circle, also shown

below.

The center is at (4938 + 0)/2 = (2469, 0 ) .

The radius is √ ( 2469)² + (3167)² = 4016 psi

So the maximum normal stress is 2469 + 4016 = 6485 psi (result)

In this case the “maximum” normal stress is tensile.

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