Beam Deflection by Superposition

 

Example:  The cantilever beam  ABC is of length L and flexural rigidity EI.  It is subjected

 to a concentrated moment, M, at midspan (B) and a concentrated load, P, at its end, C.

Find the deflection and slope of the beam at midspan, B, and at the end, C.

 

                             

 

 

Strategy:  Replace the beam under two loads with two beams each with one load as shown.

Note in the tables the concentrated moment acts at the end of the beam (top figure below.)

                      

 

From table:   yC  =  − ML2  / 2EI  and  slope  θC = − ML / EI     **  if M acted at C

                                     Also    y1(x) = − (M/2EI)  x2   for  0    x ≤  L/2

           

                    

        

From table:    yC  =  − PL3 / 3EI  and  slope ,  θC = − PL2/2EI   Also  y2(x) = (Px2/6EI)(3L – x)

 

** Since the concentrated moment, M, actually acts midspan, direct superposition will not

work.  Adjustment must be made to account for its acting at midspan prior to superposition.

 

Click here to continue this example.

 


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