Vectors
– Dot Product
Interpretation of Dot Product Let θ be the angle between U and V . U ∙ V = |U| |V| cos θ So
to calculate the angle between two vectors use: cos θ
= U ∙ V / |U| |V| |
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Example of a Dot Product Note: i ∙
i
= 1 , j
∙ j = 1
, k ∙ k = 1 ,
i ∙
j = 0, i ∙
k = 0, j ∙
k = 0 Let U =
3 i +
4 j +
5 k and V = - i + j -
6 k | U | = √ ( 32 + 42 + 52 ) = √ 50 and | V | = √ (12 + 12 + 62 ) = √ 38 U ∙ V = (3)(- 1) + (4)(1) + (5)(- 6) = - 31 (scalar result) And the angle θ between the two vectors is from cos θ = - 31 / [( √ 50 )(√ 38 )] |
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Click here for a discussion of vector products. Click here to return to a discussion of kinematics of a particle in a plane. |
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