Relative Velocity and Acceleration in a Plane – Two points in the Same Rigid Link (Body)

 

 

In a Nutshell:  Obtain the relative acceleration equation by taking the time derivative of each term in the relative velocity equation   vC  =    vA  +  ω x rAC       with respect to frame F as shown in the

figure below.

                                         dvC / dt  =   d vA /dt  +  d (ω x rAC )/dt      

 

 

                               

 

 

Now  dvC / dt  =  aC  is the acceleration of point C with respect to the fixed frame, F

 

         d vA /dt  =  aA  is the acceleration of point A with respect to the fixed frame, F

 

and  d (ω x rAC )/dt     contains two terms

 

        dω/dt x rAC  and  ω x d(rAC) /dt  

 

and as before   d(rAC) /dt  =  ω x rAC    since   rAC   can only change in direction

 

 

So the relative acceleration equation becomes

 

                 aC  =  aA  + dω/dt x rAC  +  ω x  ( ω x rAC )    and for motion in the xy plane

 

             ω x  ( ω x rAC )    =  ωk x  ( ωk x rAC )    =   ˗  ω2 rAC

 

 

Click here to continue with this discussion of relative acceleration.

 



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