Mohr’s
Circle - Stress
Example: The element shown below
has the following stresses acting on its faces. σx = 10 ksi, σy = 2 ksi, τxy =
0. Construct Mohr’s
Circle. Determine the maximum and minimum normal
stresses and the maximum shear stress.
Find the angle of the plane on which the
maximum shear stress acts. |
Strategy: Identify face A and face B on
the element. Construct Mohr’s
Circle. Rotate from plane A to determine the angle
of the plane on which the maximum shear stress occurs. The center of the circle
is at σC = (σx
+ σy)/2 = 10 + 2)/2 =
6 and τxy
= 0. So the radius of the
circle is σA
– σC = 4 ksi Note: σmax
= 10 ksi,
σmin = 2 ksi, τmax
= radius = 4 ksi The principal stresses σ1 =
10 ksi,
σ2 = 2 ksi acting on face A and face B respectively. The maximum shear stress, τmax = 4 ksi occurs at D. So rotation from A to D on Mohr’s circle is 90o clockwise. Rotation on the element is half that. So the plane on which the maximum shear stress occurs is 45o
clockwise from face A of the element shown above. On face D on the element, σx
= 6 ksi and τxy
= 4 ksi.
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